Reverse a Number -Leetcode 7 - Medium Difficulty

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123

Output: 321

Example 2:

Input: x = -123

Output: -321

Example 3:

Input: x = 120

Output: 21

 

Constraints:

-2^31 <= x <= 2^31 - 1

Code:

#include<iostream>

#include<climits>

using namespace std;

int main(int argc, char const *argv[])

{

    int number;

    cin>>number;

    int ans=0;

    while(number!=0){

        int digit=number%10;

        if(ans>INT_MAX/10 || ans<INT_MIN/10){

            cout<<0<<endl;

        }

        ans=ans*10+digit;

        number=number/10;

    }

    cout<<ans;

    return 0;

}