Adjacent Increasing Subarrays Detection I - Leetcode contest 423 Problem Solution

Link of the question:https://leetcode.com/problems/adjacent-increasing-subarrays-detection-i/

Explanation:

1. Edge case check: If the array has fewer than 2 * k elements, it's impossible to find two adjacent subarrays of length k, so we return false immediately.

2. Sliding window logic:

   • We slide through the array with a starting index i such that i goes from 0 to n - 2*k (this ensures that we have enough elements for two adjacent subarrays).
   • For each window of length k, we check if the elements within the window are strictly increasing by checking if each element is smaller than the next one.
   • Once we check the first subarray, we check the second subarray starting at i + k and ensure it's also strictly increasing.

3. Return result: If both subarrays are strictly increasing, return true. Otherwise, continue sliding through the array. If no such pair is found, return false.

Code:https://github.com/sanidhya12345/CP/blob/main/DSA/src/leetcode/AdjacentIncreasingSubarray.java

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